Rotational MotionEasy
Question
A circular disc X of radius R is made from an iron pole of thickness t, and another disc Y of radius 4R is made from an iron plate of thickness t/4. then the relation between the moment of inertia IX and IY is
Options
A.IY = 32IX
B.IY = 16IX
C.IY = 32IX
D.IY = 64IX
Solution
If t is the thickness and R is the radius of the disc, then mass = πR2tρ
ρ = density of the material of the disc.
Moment of inertia of disc X,
Ix =
πR4tρ ....(i)
Moment of inertia of disc Y,
Iy = 32 πR4tρ ....(ii)
From equation (i) and (ii)
Iy = 64 Ix
ρ = density of the material of the disc.
Moment of inertia of disc X,
Ix =
πR4tρ ....(i)Moment of inertia of disc Y,
Iy = 32 πR4tρ ....(ii)
From equation (i) and (ii)
Iy = 64 Ix
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