MagnetismHard
Question
A particle of charge -16×10-18 coulomb moving with velocity 10 ms-1 along the x-axis enters a region where a magnetic field of induction B is along the y-axis, and an electric field of magnitude 104 V/m is along the negative z-axis. If the charged particle continues moving along the x-axis, the magnitude of B is
Options
A.103Wb/m2
B.105Wb/m2
C.1016Wb/m2
D.10-3Wb/m2
Solution
.....(1)The solution of this problem can be obtained by resolving the motion along the three coordinate axes namely
ax =
(Ex + vyBz - vzBy)ay =
(Ey + vzBx - vxBz)az =
(Ez + vxBy - vyBz)For the given problem,
Ex = Ey = 0, Vy = vz = 0 and Bx = Bz = 0
Substituting in equation (2), we get
ax = az = 0 and ay = Ey - vxBz
If the particle passes through the region undeflected ay is also zero, then
Ey = vxBz
⇒ Bz =
= 103 Wb/m2Create a free account to view solution
View Solution FreeMore Magnetism Questions
Electron moves at right angles to a magnetic field of 1.5 × 10-2 tesla with speed of 6 × 107 m/s. If the speci...An α - particle moves in a circular path of radius 0.83 cm in the presence of a magnetic field of 0.25Wb/m2. The de...A magnetic neddle is kept in a non-uniform magnetic field. It may experience...Which of the following conclusion can be drawn from the result...A conductor PQ carries a current ′i′ is placed perpendicular to a long conductor XY carrying a current I. Th...