Nuclear Physics and RadioactivityHard
Question
The binding energy per nucleon of deuteron 
and helium nucleus 
is 1.1 MeV and 7 MeV respectively. If two deuteron nuclei react to form a single helium nucleus, then the energy released is
and helium nucleus is 1.1 MeV and 7 MeV respectively. If two deuteron nuclei react to form a single helium nucleus, then the energy released isOptions
A.13.9 MeV
B.26.9 MeV
C.23.6 MeV
D.19.2 MeV
Solution
Energy released = total binding energy of product - total binding energy of reactants
⇒ 28 - (2 × 2.2) = 28 - 4.4 = 236 MeV.
⇒ 28 - (2 × 2.2) = 28 - 4.4 = 236 MeV.
Create a free account to view solution
View Solution FreeMore Nuclear Physics and Radioactivity Questions
Binding energy of deuterium is 2.23 Mev, then its mass defect in a.m.u. is :-...Consider the radiation emitted by large number of singly charged positive ions of a certain element. The sample emit fif...The half - life of the radioactive radon is 3.8 days. The time , at the end of which 1 / 20th of the radon sample will r...Consider the fission reaction 92U236 → X118 + Y118 + Q (energy)The binding energy per nucleon of X and Y is 8·6 Me...A nucleus of mass M + ᐃm is at rest and decays into two daughter nuclei of equal massM/2 each. Speed of light is c...