Nuclear Physics and RadioactivityHard
Question
The binding energy per nucleon of deuteron
and helium nucleus
is 1.1 MeV and 7 MeV respectively. If two deuteron nuclei react to form a single helium nucleus, then the energy released is
and helium nucleus
is 1.1 MeV and 7 MeV respectively. If two deuteron nuclei react to form a single helium nucleus, then the energy released isOptions
A.13.9 MeV
B.26.9 MeV
C.23.6 MeV
D.19.2 MeV
Solution
Energy released = total binding energy of product - total binding energy of reactants
⇒ 28 - (2 × 2.2) = 28 - 4.4 = 236 MeV.
⇒ 28 - (2 × 2.2) = 28 - 4.4 = 236 MeV.
Create a free account to view solution
View Solution FreeMore Nuclear Physics and Radioactivity Questions
The radioactive nucleic of an element X decays to a stable nuclide of element Y. Then, in a given sample of X, the rate ...A certain mass of Hydrogen is changed to Helium by the process of fusion. The mass defect in fusion reaction is 0.02866 ...In Bohr′s atom the number of de broglie waves associated with electron moving in the permitted orbit is -...A radioactive material decays by simultaneous emission of two particles with respective half−lives 1620 and 810 ye...Mass of an α particle is :-...