ElectroMagnetic InductionHard
Question
A coil of inductance 300 mH and resistance 2Ω is connected to a source of voltage 2V. The current reaches half of its steady state value in
Options
A.0.05 s
B.0.1 s
C.0.15 s
D.0.3 s
Solution
I = I0 
e−0.693 = 1/2
0.693 =
0.1 sec
e−0.693 = 1/20.693 =
0.1 secCreate a free account to view solution
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