JEE Advanced | 2013SHMHard
Question
A particle of mass m is attached to one end of a mass-less spring of force constant k, lying on a frictionless horizontal plane. The other end of the spring is fixed. The particle starts moving horizontally from its equilibrium position at time t = 0 with an initial velocity u0. When the speed of the particle is 0.5 u0, it collides elastically with a rigid wall. After this collision :-
Options
A.the speed of the particle when it returns to its equilibrium position is u0
B.the time at which the particle passes through the equilibrium position for the first time is 

C.the time at which the maximum compression of the spring occurs is 

D.the time at which the particle passes through the equilibrium position for the second time is 

Solution
Collision is elastic so energy is conserve in given question so when it return to equilibrium, its speed is u0

by

Time period if collision not occurs
Now time to return for the first time at equilibrium

time for option (C)
time for option (D)


by


Time period if collision not occurs

Now time to return for the first time at equilibrium


time for option (C)

time for option (D)


Create a free account to view solution
View Solution FreeMore SHM Questions
A bob of mass 2m hangs by a string attached to the block of mass m of a spring block system. The whole arrangement is in...A 25 kg uniform solid sphere with a 20 cm radius is suspended by a vertical wire such that the point of suspension is ve...Two springs, each of spring constant k, are attached to a block of mass m as shown in the figure. The block can slide sm...The mass of particle executing S.H.M. is 1 gm. If its periodic time is π seconds, the value of force constant is :...Two simple harmonic motions are represented by the equation y1 = 0.1 sin and y2 = 0.1 cosπt. The phase difference o...