SHMMedium
Question
Two simple harmonic motions are represented by the equation y1 = 0.1 sin 
and y2 = 0.1 cosπt. The phase difference of the velocity of particle 1 w.r.t. the velocity of the particle 2 is at t=0
and y2 = 0.1 cosπt. The phase difference of the velocity of particle 1 w.r.t. the velocity of the particle 2 is at t=0Options
A.- π/6
B.π/3
C.-π/3
D.π/6
Solution
Phase difference (φ) = 99πt + π/3 - π/2
at t = 0 φ = - π/6.
at t = 0 φ = - π/6.
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