Laws of MotionEasy
Question
A mass of M kg is suspended by a weightless string. The horizontal force that is required to displace it until the string makes an angle of 45o with the initial vertical direction is
Options
A.Mg(√2 - 1)
B.Mg(√2 + 1)
C.Mg √2
D.
Solution
F l sin 45 = Mg (l - l cos 45)
F = Mg (√2 - 1)
F = Mg (√2 - 1)
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