CircleHard
Question
The differential equation of the family of circles with fixed radius 5 units and centre on the line y = 2 is
Options
A.(x - 2)y′2 = 25 - (y - 2)2
B.(y - 2)y′2 = 25 - (y - 2)2
C.(y - 2)2y′2 = 25 - (y - 2)2
D.(x - 2)2y′2 = 25 - (y - 2)2
Solution
(x - h)2 + (y - 2)2 = 25 ......(i)
⇒ 2(x - h) + 2(y - 2)
⇒ (x - h) = - (y - 2)
substituting in (1), we have
(y - 2)2
+ (y - 2)2 = 25
(y - 2)2y′2 = 25 - (y - 2)2.c
⇒ 2(x - h) + 2(y - 2)

⇒ (x - h) = - (y - 2)

substituting in (1), we have
(y - 2)2
+ (y - 2)2 = 25(y - 2)2y′2 = 25 - (y - 2)2.c
Create a free account to view solution
View Solution FreeMore Circle Questions
The length of the common chord of the circle x2 + y2 + 4x + 6y + 4 = 0 and x2 + y2 + 6x + 4y + 4 = 0 is-...If the circle x2 + y2 + 2x − 4y − k = 0 is midway between two circles x2 + y2 + 2x − 4y − 4 = 0 ...If the line (x + g) cos θ + (y + f) sin θ = k touches the circle x2 + y2 + 2gx + 2fy + c = 0, then -...If PQ is a chord of parabola x2 = 4 y which subtends right angle at vertex. Then locus of centroid of triangle PSQ (S is...Let x2 + y2 - 2x - 2y = 0 & x2 + y2 + 2ax + 2ay + b = 0 are two different circles. If L is the only common tangent of th...