Differential EquationHard
Question
The solution of the differential equation 
satisfying the condition y (1) = 1 is
satisfying the condition y (1) = 1 isOptions
A.y = ln x + x
B.y = x ln x + x2
C.y = xe(x-1)
D.y = x ln x + x
Solution
y = vx
⇒
∴ v = log x + c
⇒
= log x + c
Since, y (1) = 1, we have
y = x log x + x
⇒
∴ v = log x + c
⇒
= log x + c Since, y (1) = 1, we have
y = x log x + x
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