NEET | 2018Magnetic field due to currentHard

Question

A metallic rod of mass per unit len gth 0.5 kg m–1 is lying horizontally on a smooth inclined plane which makes an angle of 30° with the horizontal. The rod is not allowed to slide down by flowing a current through it when a magnetic field of induction 0.25T is acting on it in the vertical direction. The current flowing in the rod to keep is stationary is

Options

A.

7.14 A

B.

5.98 A

C.

14.76 A

D.

11.32 A

Solution


iιB cosθ = mgsinθ
i=mgιBtanθ=mιgtanθBi=0.5×9.80.25×13=11.3 amp.

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