Basic Maths and Units and DimensionsHard

Question

In the circuit shown in the figure, the input voltage Vi is 20 V, VBE = 0 and VCE = 0. The values of IB, IC and β are given by :-

Options

A.

IB = 40 μA, IC = 10 mA, β= 250

B.

IB = 25 μA, IC= 5 mA, β= 200

C.

IB = 20 μA, IC= 5 mA, β= 250

D.

IB = 40 μA, IC = 5 mA, β= 125

Solution

Vi = IBRB + VBE
20 = IB × (500 × 103) + 0
IB=20500×103=40μA
VCC= ICRC +VCE
20 = IC × (4 × 103) + 0
IC = 5 × 10–3 = 5 mA
β=ICIB=5×10-340×10-6=125

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