NEET | 2018ElectrostaticsEasy
Question
An electron falls from rest through a vertical distance h in a uniform and vertically upward
directed electric field E. The direction of electrical field is now reversed, keeping its magnitude the same. A proton is allowed to fall from rest in through the same vertical distance h. The time fall of the electron, in comparison to the time fall of the proton is :-
Options
A.
smaller
B.
5 times greater
C.
10 times greater
D.
equal
Solution
S = ut + at2
h = 0 +
as mass of proton is heavier than electron, hence electron will take less time.
Create a free account to view solution
View Solution FreeMore Electrostatics Questions
A long cylindrical shell carries positive surface charge σin the upper half and negative surface charge −�...The given figure gives electric lines of force due to two charges q1 and q2. What are the signs of the two charges?...A wheel having mass m has charges +q and -q on diametrically opposite points. It remains in equilibrium on a rough incli...Five capactiors, each of capacitance value Care connected as show in the figure. Thecapacitance between P & R,and the ca...Three charge are placed are placed at the vertices of an equilateral triangle of side ′a′ as shown in the fo...