Question

CH₃CHO $\underset{}{\overset{}{\to }}$CH₄ + CO
r₁ = 1 torr sec^-1 , when 5% reacted (95% unreacted)
r₂ = 0.5 torr sec^-1 , when 33% reacted (67% unreacted)
r $\propto$ (a - x)^m    m = order of reaction
          a-x = unreacted
$\frac{r_1}{r_2}={\left[\frac{(a-x_1)}{a-x_2}\right]}^m$
$\frac{1}{0.5}={\left(\frac{0.95}{0.67}\right)}^m$
2 = (1.41)m $\Rightarrow$ 2 = ${\left(\sqrt{2}\right)}^m$
$\Rightarrow$ m = 2