JEE Main | 2018Differential EquationHard
Question
The sum of the co-efficients of all odd degree terms in the expansion of , (x > 1) is-
Options
A.
0
B.
1
C.
2
D.
-1
Solution
using (x + a)5 + (x – a)5
= 2[5C0 x5 + 5C2 x3·a2 + 5C4x·a4]
= 2[5C0 x5 + 5C2 x3(x3 - 1) + 5C4Â x(x3 - 1)2]
2[x5 + 10x6 - 10x3 + 5x7 - 10x4 + 5x]
considering odd degree terms,
2[x5 + 5x7 - 10x3 + 5x]
Sum of coefficients of odd terms is 2
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