JEE Main | 2018Quadratic EquationHard
Question
If are the distinct roots of the equation x2 - x + 1 = 0, then is equal to-
Options
A.
0
B.
1
C.
2
D.
-1
Solution
are roots of x2 - x + 1 = 0
where is non-real cube root of unity
so,
-[-1] = 1
(As 1 + + 2 = 0 & 3 = 1)
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