JEE Main | 2018Quadratic EquationHard

Question

If α, βC are the distinct roots of the equation x2 - x + 1 = 0, thenα101 +β107 is equal to-

Options

A.

0

B.

1

C.

2

D.

-1

Solution

α, βare roots of x2 - x + 1 = 0
 α=-ω and β=-ω2
where ω is non-real cube root of unity
so, α101 + β107
 (-ω)101+(-ω2)107
 -[ω2+ω]
 -[-1] = 1 
(As 1 +ω + ω2 = 0 & ω3 = 1)

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