JEE Main | 2018CapacitanceHard

Question

A parallel plate capacitor of capacitance 90 pF is connected to a battery of emf 20V. If a dielectric material of dielectric constant K = 53 is inserted between the plates, the magnitude of the induced charge will be :-

Options

A.

0.3 n C

B.

2.4 n C

C.

0.9 n C

D.

1.2 n C

Solution


Q = (kC) V
=53×90pF(20)V
= 3000 pC
= 3nC
induced charges on dielectric
Qind = Q1-1K=3nC1-35= 1.2 nC

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