NEET | 2016Aromatic HydrocarbonsHard

Question

Which of the following statements about the composition of the vapour over an ideal 1 : 1 molar mixture of benzene and toluene is correct? Assume that the temperature is constant at 25𝑜𝐶. (Given vapour pressure data at 25𝑜𝐶, benzene = 12.8 kPa, toluene = 3.85 kPa)

Options

A.

The vapour will contain a higher percentage of benzene

B.

The vapour will contain a higher percentage of toluene

C.

The vapour will contain equal amounts of benzene and toluene.

D.

Not enough information is given to make a prediction.

Solution

A - benzene, B - Toluene
PT=PAoXA+PBoXB
= 12.8 × 0.5 + 3.85 × 0.5
= 6.2 + 1.925
= 8.125
Also, mole fraction of benzene in vapour form
𝑌𝐴 = PAoXAPT=6.28.121=0.75
And mole fraction of Toluene in vapour form
𝑌𝐵 = 1 - 0.75 = 0.25

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