NEET | 2016Aromatic HydrocarbonsHard

Question

Which of the following statements about the composition of the vapour over an ideal 1 : 1 molar mixture of benzene and toluene is correct? Assume that the temperature is constant at 25𝑜𝐶. (Given vapour pressure data at 25𝑜𝐶, benzene = 12.8 kPa, toluene = 3.85 kPa)

Options

A.

The vapour will contain a higher percentage of benzene

B.

The vapour will contain a higher percentage of toluene

C.

The vapour will contain equal amounts of benzene and toluene.

D.

Not enough information is given to make a prediction.

Solution

A - benzene, B - Toluene
PT=PAoXA+PBoXB
= 12.8 × 0.5 + 3.85 × 0.5
= 6.2 + 1.925
= 8.125
Also, mole fraction of benzene in vapour form
𝑌𝐴 = PAoXAPT=6.28.121=0.75
And mole fraction of Toluene in vapour form
𝑌𝐵 = 1 - 0.75 = 0.25

Create a free account to view solution

View Solution Free
Topic: Aromatic Hydrocarbons·Practice all Aromatic Hydrocarbons questions

More Aromatic Hydrocarbons Questions

False statement is / are :...Product obtained when benzoyl acetic acid is heated with soda-lime is:...Which of the following is formed as the major product when toluene (excess) reacts with CH3Cl at 80oC in the presence of...Reaction of SO3 is easier in -...In the sulphonation, acetylation and formylation of benzene the group of effective electrophiles would be:...