NEET | 2016Chemistry miscellaneousEasy

Question

In the reaction
H-C≡ CH→(2) CH3 CH2 Br(1) NaNH2/liq.NH2X→(2) CH3 CH2 Br(1) NaNH2/liq. NH2Y
X and Y are:

Options

A.

X = 1 - Butyne ; Y = 3 - Hexyne

B.

X = 2 - Butyne ; Y = 3 - Hexyne

C.

X = 2 - Butyne ; Y = 2 - Hexyne

D.

X = 1 - Butyne ; Y = 2 - Hexyne

Solution

H-C≡C-H→NaNH2 liq. NH3 H-C≡C_ : Na+
                                                              ↓ CH3CH2Br
Na+ : C ≡ C-CH2CH3 ←NaNH2Hiq.NH3 H-C≡C-CH2CH31-Butyne      (x)
          ↓ CH3CH2Br
CH3CH2 - C ≡C - CH2 - CH3
        3-Hexyne
            (y)
 

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