NEET | 2016Work, Power and EnergyHard

Question

40. An inductor 20 mH, a capacitor 50 μF and a resistor 40 Ω are connected in series across a source of emf V = 10 sin 340 t. The power loss in A.C. circuit is :

Options

A.

0.51 W

B.

0.67 W

C.

0.76 W

D.

0.89 W

Solution

wL = 340 ×20 ×10-3 = 68 ×10-1 = 6.8
1wC=1340×50×10-6=10434×5=234×103
= 0.0588 × 103 = 58.82
2 = mL-1wc2+R2
2 = 2704+160065.6
i =V2, 1065×2=1065.62
Power = 100×40(65.6)2×2=2000(65.6)2
= 0.51 w

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