JEE Main | 2014Dynamics and StatisticsHard

Question

The slope of the line touching both the parabolas y2 = 4x and x2 = - 32y is

Options

A.
B.
C.
D.

Solution

y2 = 4x                         .....(1)
x2 = -32y                      ....(2)
m be slope of common tangent Equation of tangent (1)
y = mx +              .........(i)
Equation of tangent (2)
     y = mx + 8m2         …(ii)
(i) and (ii) are identical
     = 8m2
⇒   m3
     
Alternative method :
Let tangent to y2 = 4x be
       y = mx +
as this is also tangent to x2 = - 32y
Solving x2 + 32mx +  = 0
Since roots are equal
∴   D = 0
 ⇒    (32)2 - 4 × = 0
 ⇒    m3 =
⇒    m = 

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