JEE Main | 2015Carboxylic Acid and Acid DerivativesHard
Question
3 g of activated charcoal was added to 50 mL of acetic acid solution (0.06N) in a flask. After an hour it was filtered and the strength of the filtrate was found to be 0.042 N. The amount of acetic acid adsorbed (per gram of charcoal) is:
Options
A.
36 mg
B.
42 mg
C.
54 mg
D.
18 mg
Solution
Amount adsorbed
= (0.060 – 0.042) X 50 X 10–3 X 60
= 0.018 X 50 X 60 X 10–3
= .018 X 3
= .054 gm= 54 mg
Amount adsorbed per gram of activated charcoal mg
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