JEE Main | 2015Carboxylic Acid and Acid DerivativesMedium

Question

3 g of activated charcoal was added to 50 mL of acetic acid solution (0.06N) in a flask. After an hour it was filtered and the strength of the filtrate was found to be 0.042 N. The amount of acetic acid adsorbed (per gram of charcoal) is:

Options

A.

36 mg

B.

42 mg

C.

54 mg

D.

18 mg

Solution

Amount adsorbed
= (0.060 – 0.042) X 50 X 10–3 X 60
= 0.018 X 50 X 60 X 10–3
= .018 X 3
= .054 gm= 54 mg
Amount adsorbed per gram of activated charcoal=543=18 mg

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