JEE Main | 2014VectorHard
Question
A student measured the length of a rod and wrote it as 3.50 cm. Which instrument did he use to measure it?
Options
A.A meter scale
B.A vernier calliper where the 10 divisions in vernier scale matches with 9 division in main scale and main scale has 10 divisions in 1 cm
C.A screw gauge having 100 divisions in the circular scale and pitch as 1 mm
D.A screw gauge having 50 divisions in the circular scale and pitch as 1 mm
Solution
As measured value is 3.50 cm, the least count must be 0.01 cm = 0.1 mm
For vernier scale with 1 MSD = 1 mm and 9 MSD = 10 VSD,
Least count = 1 MSD - 1 VSD
= 0.1 mm
For vernier scale with 1 MSD = 1 mm and 9 MSD = 10 VSD,
Least count = 1 MSD - 1 VSD
= 0.1 mm
Create a free account to view solution
View Solution FreeMore Vector Questions
A vernier callipers has 20 divisions on the vernier scale which coincide with 19 divisions on the main scale. The least ...Given that + = −. This can be true when :...If a, b, c are the percentage errors in the measurement of A, B and C then percentage error in ABC would be approximatel...What is the torque of the force = (2î − 3ĵ + 4) N, acting at the point = (3î + 2ĵ + 3)m about ...The density of a material in CGS system of unit is 4 g cm-3 . In a system of unit in whichunit of length is 10 cm and un...