JEE Main | 2014Magnetic field due to currentHard
Question
A conductor lies along the z-axis at -1.5 ≤ z < 1.5 m and carries a fixed current of 10.0 A in - 
direction(see figure). For a field 
= 3.0 × 10-4e-0.2x 
T, find the power required to move the conductor at constant speed to x = 2.0 m, y = 0 m in 5 × 10-3 s. Assume parallel motion along the x-axis
direction(see figure). For a field = 3.0 × 10-4e-0.2x T, find the power required to move the conductor at constant speed to x = 2.0 m, y = 0 m in 5 × 10-3 s. Assume parallel motion along the x-axis Options
A.1.57 W
B.2.97 W
C.14.85 W
D.29.7 W
Solution
Average Power
W =
Fdx=
3.0 × 10-4e-0.2x × 10 × 3 dx= 9 × 10-3
e-0.2 x dx=
[e-0.2 × 2 +1 ] 
× [1-e-0.4 ]= 9 × 10-3 × (0.33)
= 2.97 × 10-3 J
P =
= 2.97 WCreate a free account to view solution
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