JEE Main | 2014Errors in measurementHard
Question
The current voltage relation of diode is given by I = (e1000V/T- 1) mA, where the applied V is in volts and the temperature T is in degree kelvin. If astudent makes an error measuring ± 0.01 V while measuring the current of 5 mA at 300 K, what will be the error in the value of current in mA?
Options
A.0.2 mA
B.0.02 mA
C.0.5 mA
D.0.05 mA
Solution
I = (e1000 V/T - 1)mA
When I = 5 mA, e1000 V/T = 6 mA
Also, dI = (e1000 V/T) ×
. dV
= (6 mA)×
×(0.01)
= 0.2 mA
When I = 5 mA, e1000 V/T = 6 mA
Also, dI = (e1000 V/T) ×
. dV= (6 mA)×
×(0.01)= 0.2 mA
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