Mathematical ReasoningHard

Question

In an LCR circuit as shown below both switches are open initially. Now switch S1 is closed, S2 kept open, (q is charge on the capacitor and is Capacitive time constant). Which of the following statement is correct ?

                

Options

A.Work done by the battery is half of the energy dissipated in the resistor
B.At t= , q = CV/2
C.At t = ,q = CV(1-e-2)
D.At , q = CV(1-e-1)

Solution

For charging of capacitor
q = q0 (1 - e- t/) = CV (1 - e- t/)

at t = ,   q = CV(1 - e-2)

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