General Organic ChemistryHard
Question
A hoop of radius r and mass m rotating with an angular velocity ω0 is placed on a rough horizontal surface. The initial velocity of the centre of the hoop is zero. What will be the velocity of the centre of the hoop when it ceases to slip?
Options
A.
B.
C.
D.rω0
Solution
By angular momentum conservation about point A
Li = Lf
mR2ω0 = mvR + mR2
⇒
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