SHMHard
Question
The displacement of a particle executing SHM is given by x = 0.01 sin 100π(t + 0.05). The time period is in seconds and amplitude of the particle is in meters
Options
A.Time period of the particle is 0.02 sec.
B.Amplitude of the particle is 0.01 m
C.Time period of the particle is 0.01 sec.
D.Amplitude of the particle is 0.02 m
Solution
Time period = 0.02
Amplitude = 0.01
From given equation
= 0.02
and A = 0.01
Amplitude = 0.01
From given equation
= 0.02and A = 0.01
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