SHMHard
Question
A mass M is performing linear simple harmonic motion, then correct graph for acceleration a and corresponding linear velocity v is
Options
A.
B.
C.
D.
Solution
Velocity v = ω
⇒ v2 = ω2 A2 − ω2 x2 ....(1)
Acceleration a = − ω2x ⇒ a2 = ω4 x2 ....(2)
From (1) and (2) : v2 = ω2 A2 − a2/ω2 ⇒ v2 + a2/ω2 = ω2 A2
⇒
= 1
⇒ v2 =
its straight line with -ve slope and +ve intercept
⇒ v2 = ω2 A2 − ω2 x2 ....(1)Acceleration a = − ω2x ⇒ a2 = ω4 x2 ....(2)
From (1) and (2) : v2 = ω2 A2 − a2/ω2 ⇒ v2 + a2/ω2 = ω2 A2
⇒
= 1⇒ v2 =
its straight line with -ve slope and +ve interceptCreate a free account to view solution
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