KinematicsHard
Question
A particle is projected from a point (0, 1) on Y-axis (assume + Y direction vertically upwards) aiming towards a point (4, 9). It fell on ground along x axis in 1 sec.
Options
A.(3, 0)
B.(3, 0)
C.(2, 0)
D.(2√5, 0)
Solution
tanθ = 
= 2 ,
y = uyt +
ayt2
now − 1 = usinθ (1) −
g (1)2
usinθ = 4 and sin θ =
⇒ u = 2√5
now x = u cos θ (1) = ×
= 2m
= 2 , y = uyt +
ayt2now − 1 = usinθ (1) −
g (1)2usinθ = 4 and sin θ =
⇒ u = 2√5now x = u cos θ (1) = ×
= 2mCreate a free account to view solution
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