Hard

Question

If 4 seconds be the time in which a projectile reaches a point P of its path and 5 seconds the time from P till it reaches the horizontal plane through the point of projection . The height of P above the horizontal plane will be -  [ g = 9.8 m/sec2]

Options

A.98 meters
B.49 meters
C.196 meters
D.147 meters

Solution



or tan = = 4.5
RM − MN = h = g [(4.5)2 − (.5)2]
= 98.5.1 = 98

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