Hard
Question
A particle move along the parabolic path x = y2 + 2y + 2 in such a way that the y-component of velocity vector remains 5m/s during the motion. The magnitude of the acceleration of the particle is :
Options
A.50 m/s2
B.100 m/s2
C.10√2 m/s2
D.0.1 m/s2
Solution
= 2y 
+ 2 + 0
= 2 
+ 2y 
+ 2 
= 0. (
= 5 m/s)
= 2 (52) + 0 + 0 = 50 m/s2. Ans ″A″Create a free account to view solution
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