Laws of MotionHard
Question
In the figure shown all the surface are smooth. All the blocks A, B and C are movable X-axis is horizontal and y-axis vertical as shown. Just after the system is released from the position as shown.
Options
A.Acceleration of ′A′ relative to ground is in negative y-direction
B.Acceleration of ′A′ relative to B is in positive x-direction
C.The horizontal acceleration of ′B′ relative to ground is in negative x-direction.
D.The acceleration of ′B′ relative to ground directed along the inclined surface of ′C′ is greater than g sin θ.
Solution
There is no horizontal force on block A, therefore it does not move in x-directing, whereas there is net downward force (mg − N) is acting on it, making its acceleration along negative y-direction.
Block B moves downward as well as in negative x-direction. Downward acceleration of A and B will be equal due to constrain, thus w.r.t. B, A moves in positive x-direction.
Due to the component of normal exerted by C on B, it moves in negative x-direction.
Block B moves downward as well as in negative x-direction. Downward acceleration of A and B will be equal due to constrain, thus w.r.t. B, A moves in positive x-direction.
Due to the component of normal exerted by C on B, it moves in negative x-direction.
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