Laws of MotionHard
Question
System is shown in the figure. Assume that cylinder remains in contact with the two wedges. The velocity of cylinder is -
Options
A.
m/s
m/sB.
m/s
m/sC.√3u m/s
D.√7u m/s
Solution
(D)
Method - I
As cylinder will remains in contact with wedge A
Vx = 2u
As it also remain in contact with wedge B
u sin 30o = Vy cos30° – Vx sin30o
Vy = Vx
Vy = Vx tan30o + u tan 30o
Vy = 3u tan30o = √3 u
V =
= √7 u Ans.
Method - II
In the frame of A
3u sin 30o = Vycos30o
⇒ Vy = 3u tan 30o = √3u
and Vx = 2u ⇒ V =
= √7 u Ans.
Method - I
As cylinder will remains in contact with wedge A
Vx = 2u
As it also remain in contact with wedge B
u sin 30o = Vy cos30° – Vx sin30o
Vy = Vx
Vy = Vx tan30o + u tan 30o
Vy = 3u tan30o = √3 u
V =
= √7 u Ans. Method - II
In the frame of A
3u sin 30o = Vycos30o
⇒ Vy = 3u tan 30o = √3u
and Vx = 2u ⇒ V =
= √7 u Ans. Create a free account to view solution
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