Laws of MotionHard
Question
A uniform rope of length L and mass M is placed on a smooth fixed wedge as shown. Both ends of rope are at same horizontal level. The rope is initially released from rest, then the magnitude of initial acceleration of rope is
Options
A.Zero
B.M( cosα − cos β) g
C.M(tan α − tan β)g
D.None of these
Solution
Let L1 and L2 be the portions (of length) of rope on
left and right surface of wedge as shown
∴ magnitude of acceleration of rope
a =
= 0 (Q L1 sinα = L2 sinβ)Create a free account to view solution
View Solution FreeMore Laws of Motion Questions
Working of rocket or jet is based on :-...A particle moves in the X-Y plane under the influence of a force such that its linear momentum is (t) = A[cos(kt) - sin(...A bird is sitting in a wire cage hanging from the spring balance. Let the reading of the spring balance be w1. If the bi...The rear side of a truck is open and a box of mass 20 kg is placed on the truck 4m away from the open end, μ = 0.15...Two bodies of masses 4 kg and 5 kg are acted upon by the same force. If the acceleration of lighter body is 2m/sec2, the...