Laws of MotionMedium
Question
A uniform rope of length L and mass M is placed on a smooth fixed wedge as shown. Both ends of rope are at same horizontal level. The rope is initially released from rest, then the magnitude of initial acceleration of rope is
Options
A.Zero
B.M( cosα − cos β) g
C.M(tan α − tan β)g
D.None of these
Solution
Let L1 and L2 be the portions (of length) of rope on
left and right surface of wedge as shown
∴ magnitude of acceleration of rope
a =
= 0 (Q L1 sinα = L2 sinβ)Create a free account to view solution
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