Laws of MotionHard
Question
A uniform rope of length L and mass M is placed on a smooth fixed wedge as shown. Both ends of rope are at same horizontal level. The rope is initially released from rest, then the magnitude of initial acceleration of rope is
Options
A.Zero
B.M( cosα − cos β) g
C.M(tan α − tan β)g
D.None of these
Solution
Let L1 and L2 be the portions (of length) of rope on
left and right surface of wedge as shown
∴ magnitude of acceleration of rope
a =
= 0 (Q L1 sinα = L2 sinβ)Create a free account to view solution
View Solution FreeMore Laws of Motion Questions
If the force on a rocket, moving with a velocity 500m/s is 400N, then the rate of combustion of the fuel will be :...A block of 5 kg is placed on horizontal plane. Cofficient of static and kinetic friction are 0.6 and 0.4 respectively. B...The ratio of weight of a man in a stationary lift and in a lift accelerating downwards with a uniform acceleration is 3 ...Three identical blocks of masses m = 2kg are drawn by a force F = 10.2 N with an acceleration of 0.6 ms-2 on a frictions...The ratio of gravitational mass to inertial mass is equal to :...