ProbabilityHard
Question
Three of the six veritices of a regular hexagon are chosen at random. The probability that triangle with three vertices is equilateral, equals
Options
A.1/2
B.1/5
C.1/10
D.1/20
Solution
Three vertices out of 6 can be chosen in 6C3 ways.
So, total ways = 6C3 = 20
Only two equilateral triangles can be formed ᐃAEC and ᐃ BFD
So, favourable ways = 2
So, required probabiilyy
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