Laws of MotionHard
Question
Two beads A and B move along a semicircular wire frame as shown in figure. The beads are connected by an inelastic string which always remains tight. At an instant the speed of A is u, ⎳BAC = 45o and ⎳BOC = 75o where O is the centre of the semicircular arc. The speed of bead B at that instant is :


Options
A.√2 u
B.u
C.
D.
Solution
(A) u cos 45o = v cos 60o
or v = √2 u
or v = √2 uCreate a free account to view solution
View Solution FreeMore Laws of Motion Questions
Two block of mass m1 and m2 are connected with a mass less spring and placed over a plank moving with an acceleration &#...A uniform rope of length L and mass M is placed on a smooth fixed wedge as shown. Both ends of rope are at same horizont...Two persons, pull each other through a massless rope in ′tug of war′ game. Who will win :-...Two persons are holding a rope of negligible weight tightly at its ends so that it is horizontal. A 15 kg weight is atta...Two block A and B of masses m & 2m respectively are held at rest such that the spring is in natural length. What is the ...