Laws of MotionHard
Question
A rod AB is shown in figure. End A of the rod is fixed on the ground. Block is moving with velocity √3 m/s towards right. The velocity of end B of rod when rod makes an angle of 60o with the ground is:
Options
A.√3 m/s
B.2 m/s
C.2√3 m/s
D.3 m/s
Solution
Let AB = l , B = (x , y)
= vxî + vyĵ
= √3î + vyĵ → (i)
x2 + y2 = l2
2x vx + 2y vy = 0 ⇒ √3 +
vy = 0
⇒ √3 + (tan60o) vy = 0
⇒ vy = − 1
Hence from (i)
= √3 î − ĵ
Hence
vB = 2 m/s
= vxî + vyĵ= √3î + vyĵ → (i)x2 + y2 = l2
2x vx + 2y vy = 0 ⇒ √3 +
vy = 0 ⇒ √3 + (tan60o) vy = 0
⇒ vy = − 1
Hence from (i)
= √3 î − ĵ Hence
vB = 2 m/s
Create a free account to view solution
View Solution FreeMore Laws of Motion Questions
Two blocks each having a mass M are placed as shown in the figure. The acceleration of the system is :-...In the arrangement show in figure, coefficient of friction between the two block is μ = . The force of friction act...A force applied on a mass is represented as and accelerates with 1 m/s2. What will be the mass of the body :-...In the arrangement show in figure m1=1kg, m2=2kg. pulleys are mass less and strings are light. For What value of M the m...Two force are simultaneously applied on an object. What third force would make the net force to point to the left (-x di...