Laws of MotionMedium
Question
In the arrangement shown in fig. the ends P and Q of an unstretchable string move downwards with uniform speed U. Pulleys A and B are fixed. Mass M moves upwards with a speed.
Options
A.2 U cos q
B.U cos θ
C.2U/cos θ
D.U/cos θ
Solution
By symmetry we can conclude that block will move only in vertical direction.
Length of string AB remains constant
∴ Velocity of point A and B along the string is same.
V cos θ = u ⇒ V =
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