ProbabilityMedium
Question
Let 0 < P (A) < 1, 0 < P(B) < 1 and P(A ∪ B) = P(A) + P(B) - P(A)P(B), then
Options
A.P(B / A) = P(B) - P(A)
B.P(A′- B′) = P(A′) - P(B′)
C.P(A ∪ B)′ = P(A)′ P(B)′
D.P(A / B) = P(A) - P(B)
Solution
Since, P(A ∩ B) = P(A).P(B)
It means A and are independent events so A′ and B′ are also independent.
∴ P(A ∪ B)′ = P(A ∩ B)′
= P(A′).P(B′)
It means A and are independent events so A′ and B′ are also independent.
∴ P(A ∪ B)′ = P(A ∩ B)′
= P(A′).P(B′)
Create a free account to view solution
View Solution FreeMore Probability Questions
If A and B be any two events, then P (AB) equals-...Odds 8 to 5 against a person who is 40 years old living till he is 70 and 4 to 3 against another person now 50 till he w...5 different games are to be distributed among 4 children randomly. The probability that each child gets atleast one game...The probability that a bulb produced by a factory will fuse after 150 days of use is 0.05. What is the probability that ...Two dice are thrown. What is the probability that the sum of the numbers appearing on the two dice is 11, if 5 appears o...