ProbabilityHard
Question
Let 0 < P (A) < 1, 0 < P(B) < 1 and P(A ∪ B) = P(A) + P(B) - P(A)P(B), then
Options
A.P(B / A) = P(B) - P(A)
B.P(A′- B′) = P(A′) - P(B′)
C.P(A ∪ B)′ = P(A)′ P(B)′
D.P(A / B) = P(A) - P(B)
Solution
Since, P(A ∩ B) = P(A).P(B)
It means A and are independent events so A′ and B′ are also independent.
∴ P(A ∪ B)′ = P(A ∩ B)′
= P(A′).P(B′)
It means A and are independent events so A′ and B′ are also independent.
∴ P(A ∪ B)′ = P(A ∩ B)′
= P(A′).P(B′)
Create a free account to view solution
View Solution FreeMore Probability Questions
If X follows a binomial distribution with parameters n = 8 and p = 1/2, then P (| X − 4 | ≤ 2) equals-...India plays two matches each with West Indies and Australia. In any match the probability to get 0,1 and 2 point by Indi...Three numbers are chosen at random without replacement from {1, 2, 3,......, 10}. The probability that the minimum of th...If A and B are any two events such that P (A + B) = 5/6, P (AB) = 1/3, P () =1/2, then the events A and B are-...A card is drawn from a pack of 52 cards. The probability that the card drawn is neither a heart nor a king is-...