Laws of MotionMedium
Question
A constant force F is applied in horizontal direction as shown. Contact force between M and m is N and between m and M′ is N′ then


Options
A.N = N′
B.N > N′
C.N′ > N
D.cannot be determined
Solution

F − N = Ma [Newtons law for block of mass M]
N − N′ = ma [Newtons law for block of mass m]
N′ = M′a [Newtons law for block of mass M′]
⇒ N′ = M′
N = (m + M′)
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