Photoelectric EffectHard
Question
A 
B 
C
t = 0 N0 0 0
t N1 N2 N3
In the above radioactive decay C is stable nucleus. Then:
B Ct = 0 N0 0 0
t N1 N2 N3
In the above radioactive decay C is stable nucleus. Then:
Options
A.rate of decay of A will first increase and then decrease
B.number of nuclei of B will first increase and then decrease
C.if λ2 > λ1, then activity of B will always be higher than activity of A
D.if λ2 > λ1, then number of nucleus of C will always be less than number of nucleus of B.
Solution
Rate of decay of A keeps on decreasing continuously because concentration of A decreases with time. ⇒ A is false
Initial rate of production of B is λ1N0 and rate of decay is zero. With time, as the number of B atom increase, the rate of its production decrease and its rate of decay increases. Thus the number of nuclei of B will first increase and then decrease. ⇒ B is the correct choice
The initial activity of B is zero whereas initial activity of A is λ1N0 ⇒ C is false.
As time t → ∞ : NA = 0, NB = 0 and NC = N0. ⇒ D is false
Initial rate of production of B is λ1N0 and rate of decay is zero. With time, as the number of B atom increase, the rate of its production decrease and its rate of decay increases. Thus the number of nuclei of B will first increase and then decrease. ⇒ B is the correct choice
The initial activity of B is zero whereas initial activity of A is λ1N0 ⇒ C is false.
As time t → ∞ : NA = 0, NB = 0 and NC = N0. ⇒ D is false
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