ProbabilityHard
Question
The probability that an event A happens in one trial of an experiment is 0.4. Three independent trials of the experments are performed. The probability that the event A happens at lest ones is
Options
A.0.936
B.0.784
C.0.904
D.None of the above
Solution
Givent that, P(A) = 0.4, P
= 0.6
P (the event A happents at least one )
= 1 - P(none of the event happens)
= 1 - (0.6)(0.6)(0.6) = 1 - 0.216 = 0.784
= 0.6 P (the event A happents at least one )
= 1 - P(none of the event happens)
= 1 - (0.6)(0.6)(0.6) = 1 - 0.216 = 0.784
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