Photoelectric EffectHard
Question
Two isotopes P and Q of atomic weight 10 and 20, respectively are mixed in equal amount by weight. After 20 days their weight ratio is found to be 1 : 4. Isotope P has a half-life of 10 days. The half-life of isotope Q is
Options
A.zero
B.5 days
C.20 days
D.inifinite
Solution
No. of nucleus of P, NP =
× NA
No. of nucleus of Q, NQ =
No. of Isotope P after 20 days, NP′ =
Let no. of Isotope Q after 20 days be NQ′
∴
(given)
NQ′ = 2 × NP′ =
= NQ
Thus no change in number of Q. Hence its half life is infinity.
No. of nucleus of Q, NQ =
No. of Isotope P after 20 days, NP′ =
Let no. of Isotope Q after 20 days be NQ′
∴
NQ′ = 2 × NP′ =
Thus no change in number of Q. Hence its half life is infinity.
Create a free account to view solution
View Solution FreeMore Photoelectric Effect Questions
When electron is incident on molyblednum then by changing energy of electron :-...The solution of Bragg′s equation is possible if :...A 200 W sodium street lamp emits yellow light of wavelength 0.6 μm. Assuming it to be 25% efficientin converting el...The mass number of a nucleus is...A B Ct = 0 N0 0 0 t N1 N2 N3In the above radioactive decay C is stable nucleus. Then:...