Photoelectric EffectHard
Question
Two isotopes P and Q of atomic weight 10 and 20, respectively are mixed in equal amount by weight. After 20 days their weight ratio is found to be 1 : 4. Isotope P has a half-life of 10 days. The half-life of isotope Q is
Options
A.zero
B.5 days
C.20 days
D.inifinite
Solution
No. of nucleus of P, NP =
× NA
No. of nucleus of Q, NQ =
No. of Isotope P after 20 days, NP′ =
Let no. of Isotope Q after 20 days be NQ′
∴
(given)
NQ′ = 2 × NP′ =
= NQ
Thus no change in number of Q. Hence its half life is infinity.
No. of nucleus of Q, NQ =
No. of Isotope P after 20 days, NP′ =
Let no. of Isotope Q after 20 days be NQ′
∴
NQ′ = 2 × NP′ =
Thus no change in number of Q. Hence its half life is infinity.
Create a free account to view solution
View Solution FreeMore Photoelectric Effect Questions
In Q. 12, the potential energy of the electron is :...The bulk modulus of a metal is 1010 N/ m2 and Poisson′s ratio 0.20 If average distance between the molecules is 3A...The work- function of a substance is 4.0 eV. The longest wavelength of light that can cause photoelectron emission from ...The different lines in the Lyman series have their wavelengths lying between :...In photoelectric emission process from a metal of workfunction 1.8 eV, the kinetic energymost energetic electron is 0.5 ...