Photoelectric EffectHard
Question
When a hydrogen atom is excited from ground state to first excited state then
Options
A.its kinetic energy increases by 10.2 eV.
B.its kinetic energy decreases by 10 .2 eV.
C.its kinetic energy decreases by 10 .2 eV.
D.its angular momentum increases by 1.05 × 10-34 J-s.
Solution
K.E. = 
eV, P.E = 
eV for Hydrogen z = 1
ᐃK = Kf − Ki z = 1
ᐃK.E. =
= − 10.2 eV (decrease)
= (PE)f − (PE)i
ᐃP.E. =
= 20.4 eV (increase)
Angular momentum L =
ᐃL =
(2 − 1) = 
= 1.05 × 10-34 J-s (increase)
eV, P.E = eV for Hydrogen z = 1ᐃK = Kf − Ki z = 1
ᐃK.E. =
= − 10.2 eV (decrease) = (PE)f − (PE)i
ᐃP.E. =
= 20.4 eV (increase)Angular momentum L =
ᐃL =
(2 − 1) = = 1.05 × 10-34 J-s (increase)Create a free account to view solution
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