Atomic StructureMedium
Question
The total energy of the electron in the first excited state of hydrogen is − 3.4 eV. What is the kinetic energy of the electron in this state ?
Options
A.+ 1.7 eV
B.+ 1.7 eV
C.+ 6.8 eV
D.− 13.4 eV
Solution
In quantum state of a bohr atom −T.E = KE
−(−3.4) = KE
3.4 ev = KE
−(−3.4) = KE
3.4 ev = KE
Create a free account to view solution
View Solution FreeMore Atomic Structure Questions
In the following diagram, which particle has highest e/m value?...A stationary hydrogen atom of mass M emits a photon corresponding to the first line of lyman series. If R is the Rydberg...$7.9MeV\alpha$-particle scatters from a target material of atomic number 79. From the given data the estimated diameter ...When a hydrogen atom is excited from ground state to first excited state then...Electron in hydrogen atom first jumps from third excited state to second excited state and then fromsecond excited to th...