Atomic StructureMedium
Question
The total energy of the electron in the first excited state of hydrogen is − 3.4 eV. What is the kinetic energy of the electron in this state ?
Options
A.+ 1.7 eV
B.+ 1.7 eV
C.+ 6.8 eV
D.− 13.4 eV
Solution
In quantum state of a bohr atom −T.E = KE
−(−3.4) = KE
3.4 ev = KE
−(−3.4) = KE
3.4 ev = KE
Create a free account to view solution
View Solution FreeMore Atomic Structure Questions
If 13.6 eV energy is required to ionize the hydrogen atom, then the energy required to remove an electron from n = 2 is ...Match List I of the nuclear processes with List II containing parent nucleus and one of the end productsof each process ...Angular momentum of an electron in a hydrogen atom is $\frac{3\text{ }h}{\pi}$, then the energy of the electron is $\_\_...When a hydrogen atom, initially at rest emits a photon resulting in transition n = 5 → n = 1. its recoil speed is ...If a0 is the Bohr radius, the radius of the n = 2 electronic orbit in triply ionized beryllium is -...