KTGHard
Question
The internal energy of an ideal gas is equal to negative of the work done by the system, then
Options
A.The process must be adiabatic
B.The process must be isothermal
C.The process must be isobaric
D.The temperature must decrease
Solution
As ᐃQ = ᐃU + W
ᐃU = − W (give)
or ᐃQ = 0
∴ Process is adiabatic
ᐃU = − W (give)
or ᐃQ = 0
∴ Process is adiabatic
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