KTGMedium
Question
Three closed vessels A, B, and C are at the same temperature T and contain gases which obey the Maxwell distribution of speed . Vessel A contains only O2, B only N2 and C a mixture of equal quantities of O2 and N2. If the average speed of O2 molecules in vessel A is V1, that of the N2 molecules in vessel B is V2 ,the average speed of the O2 molecules in vessel C will be :
Options
A.(V1 + V2)/2
B.V1
C.(V1V2)1/2
D.
Solution
Vav =
, VAV α √T
For same temp in vessel A, B and C, Average speed of O2 molecule is same in vessel A and C and is equal to V1.
For same temp in vessel A, B and C, Average speed of O2 molecule is same in vessel A and C and is equal to V1.
Create a free account to view solution
View Solution FreeMore KTG Questions
Two moles of monoatomic gas are mixed with 1 mole of a diatomic gas. The γγ for the mixture is :...A gas mixture consists of 2 moles of oxygen and 4 moles of argon at temperature T. Neglecting all vibrational modes, the...The amount of heat energy required to raise the temperature of 1 g of Helium at NTP, from T1 K to T2 K is :-...Graph shows a hypothetical speed distribution for a sample of N gas particle (for V > V0; = 0)...Temperature of an ideal gas is 300 K. The change in temperature of the gas when its volume changes from V to 2V in the p...