ProbabilityHard
Question
Box-I contains 5 red and 4 blue balls while box-II contains 4 red and 2 blue balls. A fair die is thrown. If it turns up a multiple of 3, a ball is drawn from box-I, else a ball is drawn from box-II. Find the probabiliy of the event ′ball drawn is from box-I, if it is blue′.
Options
A.1/6
B.15/19
C.4/19
D.2/5
Solution
A → Ball from Box I, P(A) = 
P(E/A) = 4/9
B → Ball from Box II P(B) =
P(E/B) = 2/6
E → Ball drawn is Blue
By use of Bays theorem
P(A/E) =
P(E/A) = 4/9B → Ball from Box II P(B) =
P(E/B) = 2/6E → Ball drawn is Blue
By use of Bays theorem
P(A/E) =
Create a free account to view solution
View Solution FreeMore Probability Questions
A pair of dice is thrown. If 5 appears on at least one of the dice, then the probability that the sum is 10 or greater, ...P (A + B) means-...The odd against throwing 10 with two dice in a throw are-...A number is chosen at random from the numbers 10 to 99. A number whose product of digits is 12 will be called a good num...A random variable X has the probability distribution: For the events E = {X is a prime number} and F = {X...