Fluid MechanicsMedium
Question
A 10 cm side cube weighing 5N is immersed in a liquid of relative density 0.8 contained in a rectangular tank of cross section a area 15cm x 15cm. If the tank contained liquid to a height of 8 cm before the immersion, the level of the liquid surface is :
Options
A.
cm
cmB.
cm
cmC.10 cm
D.11 cm
Solution
Given: ρc × (10)3 × g = 5 × 105 dynes ⇒ ρc = 0.5; g = 1000 cm/s2, Buoyant force should balance weight ⇒ ρl Vl g = 5 × 105 ⇒ Vl = 625 cm3, ∴ depth upto which cube is dipped is ⇒ 625 = 10 × 10 × d ⇒ d = 6.25 cm. Now, 15 × 15 × h = 15 × 15 × 8 + 625 ⇒ h = 97/9 [ ρc (density of cube), ρl (density of liquid), Vl (volume of liquid displacement)]
Create a free account to view solution
View Solution FreeMore Fluid Mechanics Questions
Water flows in a streamline motion through a horizontal pipe of circular cross-section as shown in the figure. The press...A tube of length L is filled completely with an incompressible liquid of mass M and closed at both ends. The tube is the...A large open tank has two holes in the wall. One is square hole of side L at a depth y from from the top and the other i...A balloon is made of a material of surface tension $S$ and its inflation outlet (from where gas is filled in it) has sma...A block of steel of size 5 cm. x 5 cm. x 5 cm. is weighed in water. If the relative density of steel is 7, its apparent ...