Fluid MechanicsMedium
Question
A block of silver of mass 4 kg hanging from a string is immersed in a liquid of relative density 0.72. If relative density of silver is 10, then tension in the string will be : [take g = 10 m/s2]
Options
A.37.12 N
B.42 N
C.73 N
D.21 N
Solution
Let ρS, ρL be the density of silver and liquid. Also m and V be the mass and volume of silver block.
∴ Tension in string = mg − buoyant force
T = ρSVg − ρL Vg = (ρS − ρL) Vg
Also V =
∴ T =
mg = 
× 4 × 10
= 37.12 N.
∴ Tension in string = mg − buoyant force
T = ρSVg − ρL Vg = (ρS − ρL) Vg
Also V =
∴ T =
mg = × 4 × 10= 37.12 N.
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